Đáp án:
c) \(x \in \emptyset \)
Giải thích các bước giải:
\(\begin{array}{l}
a)2x = \dfrac{{1 + 14}}{{15}}\\
\to 2x = 1\\
\to x = \dfrac{1}{2}\\
b)\left| {2x - 3} \right| - \dfrac{{11}}{4} = \dfrac{1}{{49}}\\
\to \left| {2x - 3} \right| = \dfrac{{543}}{{196}}\\
\to \left[ \begin{array}{l}
2x - 3 = \dfrac{{543}}{{196}}\\
2x - 3 = - \dfrac{{543}}{{196}}
\end{array} \right.\\
\to \left[ \begin{array}{l}
x = \dfrac{{1131}}{{392}}\\
x = \dfrac{{45}}{{392}}
\end{array} \right.\\
c){\left( {2x - 3} \right)^{x + 3}} = {\left( {2x - 3} \right)^{x + 1}}\\
\Leftrightarrow x + 3 = x + 1\\
\Leftrightarrow - 3 = 1\left( l \right)\\
\to x \in \emptyset
\end{array}\)