Em tham khảo nha:
\(\begin{array}{l}
40)\,A\\
CH \equiv CH + {H_2} \xrightarrow{xt,t^0} C{H_2} = C{H_2}\\
nC{H_2} = C{H_2} \xrightarrow{xt,t^0} {( - C{H_2} - C{H_2} - )_n}\\
41)\,B\\
CH \equiv CH + HCl \xrightarrow{xt,t^0} C{H_2} = CHCl\\
nC{H_2} = CHCl \xrightarrow{xt,t^0} {( - C{H_2} - CHCl - )_n}
\end{array}\)
