Đáp án:
3) \(x = - \dfrac{{3}}{{18}}\)
Giải thích các bước giải:
\(\begin{array}{l}
1){x^2} - 4x + 4 - {x^2} + 9 = 6\\
\to - 4x = - 7\\
\to x = \dfrac{7}{4}\\
4){x^2} - 8x + 16 - {x^2} + 4 = 6\\
\to - 8x = - 14\\
\to x = \dfrac{7}{4}\\
2)4\left( {{x^2} - 6x + 9} \right) - 4{x^2} + 1 = 10\\
\to 4{x^2} - 24x + 32 - 4{x^2} + 1 = 10\\
\to - 24x = - 23\\
\to x = \dfrac{{23}}{{24}}\\
3)9\left( {{x^2} + 2x + 1} \right) - 9{x^2} + 4 = 10\\
\to 9{x^2} + 18x + 9 - 9{x^2} + 4 = 10\\
\to 18x = - 3\\
\to x = - \dfrac{{3}}{{18}}
\end{array}\)
