Em tham khảo nha :
Câu 2:
\(\begin{array}{l}
a)\\
{C_n}{H_{2n + 2}}{O_m} + \dfrac{{3n + 1 - m}}{2}{O_2} \xrightarrow{t^0} nC{O_2} + (n + 1){H_2}O\\
{n_{{C_n}{H_{2n + 2}}{O_m}}} = {n_{{H_2}O}} - {n_{C{O_2}}} = 0,3 - 0,2 = 0,1mol\\
{M_{{C_n}{H_{2n + 2}}{O_m}}} = \dfrac{{4,6}}{{0,1}} = 46dvC\\
{n_C} = {n_{C{O_2}}} = 0,2mol\\
n = \dfrac{{{n_C}}}{{{n_{{C_n}{H_{2n + 2}}{O_m}}}}} = \dfrac{{0,2}}{{0,1}} = 2\\
\Rightarrow CTPT:{C_2}{H_6}{O_m}\\
m = \dfrac{{46 - 12 \times 2 + 6}}{{16}} = 1\\
\Rightarrow CTPT:{C_2}{H_6}O\\
b)\\
CTCT:\\
C{H_3} - C{H_2} - OH\\
C{H_3} - O - C{H_3}
\end{array}\)