Em tham khảo nha:
Em xem lại đề nhé
\(\begin{array}{l}
a)\\
2{C_2}{H_6} + 7{O_2} \to 4C{O_2} + 6{H_2}O\\
{C_5}{H_{12}} + 8{O_2} \to 5C{O_2} + 6{H_2}O\\
n{O_2} = \dfrac{{33,6}}{{22,4}} = 1,5\,mol\\
n{H_2}O = \dfrac{{21,6}}{{18}} = 1,2\,mol\\
hh:{C_2}{H_6}(a\,mol),{C_5}{H_{12}}(b\,mol)\\
7a + 8b = 1,5\\
3a + 6b = 1,2\\
\Rightarrow a = - 0,033;b = 0,2167
\end{array}\)