$\frac{x^{2}-4x+4}{3}$ -$\frac{4x^{2}+9}{8}$ +$\frac{x^{2}-8x+16}{6}$ =0;
<=> $\frac{8x^{2}-32x+32}{24}$ -$\frac{12x^{2}+27}{24}$ +$\frac{4x^{2}-32x+64}{24}$ =0;
<=> $\frac{8x^{2}-32x+32-12x^{2}-27+4x^{2}-32x+64}{24}$ =$\frac{-64x+69}{24}$ =0;
x=$\frac{69}{64}$