Đáp án:
Giải thích các bước giải:
$\sqrt{2}x-3y=2006\Rightarrow 2x-3\sqrt{2}y=2006\sqrt{2}(1)\\
2x+\sqrt{3}y=2007 (2)\\
(1)-(2) \Rightarrow -3\sqrt{2}y-\sqrt{3}y=2006\sqrt{2}-2007\\
\Leftrightarrow (-3\sqrt{2}-\sqrt{3})y=2006\sqrt{2}-2007 \Rightarrow y=\frac{2006\sqrt{2}-2007}{-3\sqrt{2}-\sqrt{3}}\\
\Rightarrow x=\frac{2007-\sqrt{3}.\frac{2006\sqrt{2}-2007 }{-3\sqrt{2}-\sqrt{3}}}{2}=\frac{2007-\frac{2006\sqrt{2}-2007 }{-\sqrt{6}-1}}{2}=\frac{2007\sqrt{6}+2007+2006\sqrt{2}-2007 }{2(\sqrt{6}+1)}=\frac{2007\sqrt{6}+2006\sqrt{2} }{2(\sqrt{6}+1)}=\frac{2007\sqrt{3}+2006 }{\sqrt{2}(\sqrt{6}+1)}$
