Đáp án:
\(\left[ \begin{array}{l}x=\dfrac{\pi}{3}+k\pi\\x=\dfrac{7\pi}{6}+k\pi\end{array} \right.\)`(kinZZ)`
Giải thích các bước giải:
`sin(2x-pi)=-sqrt3/2`
`<=>sin(2x-pi)=sin(-pi/3)`
`<=>`\(\left[ \begin{array}{l}2x-\pi=-\dfrac{\pi}{3}+k2\pi\\2x-\pi=\pi+\dfrac{\pi}{3}+k2\pi\end{array} \right.\)
`<=>`\(\left[ \begin{array}{l}2x=\dfrac{2\pi}{3}+k2\pi\\2x=\dfrac{7\pi}{3}+k2\pi\end{array} \right.\)
`<=>`\(\left[ \begin{array}{l}x=\dfrac{\pi}{3}+k\pi\\x=\dfrac{7\pi}{6}+k\pi\end{array} \right.\)`(kinZZ)`