Ta có :
a. $\frac{3}{2.5}$ + $\frac{3}{5.8}$ + $\frac{3}{8.11}$ + ... + $\frac{3}{101.104}$
= $\frac{1}{2}$ - [ $\frac{1}{5}$ + $\frac{1}{5}$ - $\frac{1}{8}$ + $\frac{1}{y}$ - $\frac{1}{11}$ +...+ $\frac{1}{101}$ ] - $\frac{1}{104}$
= $\frac{1}{2}$ - 0 - 0 - 0 - .... - 0 - $\frac{1}{104}$
= $\frac{1}{2}$ - $\frac{1}{104}$
= $\frac{51}{104}$