Đáp án + giải thích các bước giải:
`\sqrt{8+2\sqrt{7}}=\sqrt{7+2\sqrt{7}+1}=\sqrt{(\sqrt{7}+1)^2}=|\sqrt{7}+1|=\sqrt{7}+1`
`\sqrt{4-2\sqrt{3}}=\sqrt{3-2\sqrt{3}+1}=\sqrt{(\sqrt{3}-1)^2}=|\sqrt{3}-1|=\sqrt{3}-1`
`\sqrt{6+2\sqrt{5}}=\sqrt{5+2\sqrt{5}+1}=\sqrt{(\sqrt{5}+1)^2}=|\sqrt{5}+1|=\sqrt{5}+1`
`\sqrt{12-2\sqrt{11}}=\sqrt{11-2\sqrt{11}+1}=\sqrt{(\sqrt{11}-1)^2}=|\sqrt{11}-1|=\sqrt{11}-1`
`\sqrt{14+2\sqrt{13}}=\sqrt{13+2\sqrt{13}+1}=\sqrt{(\sqrt{13}+1)^2}=|\sqrt{13}+1|=\sqrt{13}+1`
