`|2x+1|=|3x-2|`
`<=>`\(\left[ \begin{array}{l}2x+1=3x-2\\2x+1=-(3x-2)\end{array} \right.\)
`<=>`\(\left[ \begin{array}{l}2x+1-3x+2=0\\2x+1+3x-2=0\end{array} \right.\)
`<=>`\(\left[ \begin{array}{l}-x+3=0\\5x-1=0\end{array} \right.\)
`<=>`\(\left[ \begin{array}{l}-x=-3\\5x=1\end{array} \right.\)
`<=>`\(\left[ \begin{array}{l}x=3\\x=\dfrac{1}{5}\end{array} \right.\)
Vậy `x=3,x=1/5`
