Đáp án:
$\dfrac{-13}{6}$
Giải thích các bước giải:
$-1,6.\left [ (-2013)^0-\dfrac{2}{-3} \right ]+\dfrac{1}{8}:(-0,5)^2\\
=\dfrac{-16}{10}.\left [ 1+\dfrac{2}{3} \right ]+\dfrac{1}{8}:\left (\dfrac{-1}{2} \right )^2\\
=\dfrac{-8}{5}.\left [ \dfrac{3}{3}+\dfrac{2}{3} \right ]+\dfrac{1}{8}:\dfrac{1}{4} \\
=\dfrac{-8}{5}. \dfrac{5}{3}+\dfrac{1}{8}.4 \\
=\dfrac{-8}{3}+\dfrac{1}{2} \\
=\dfrac{(-8).2}{6}+\dfrac{3}{6} \\
=\dfrac{-16+3}{6}\\
=\dfrac{-13}{6}$
