Bạn tham khảo :
$A = 1 + 2 + 3 + ... + n$
⇒ $A = n - 1:1+1 = n - 1+1 = n$
$B= 1 + 3 + 5 + ... +( 2 n - 1 )$
⇒ $B = (n-1) . n(n-1) :2$
$C = 1 × 2 + 2 × 3 + 3 × 4 +..... + n × (n + 1)$
⇒ $C = (2n - 1 - 1) : 2 + 1 = 2n : 2 + 1 = 1n + 1 = 2n$
$D = 1 × 2 × 3 + 2 × 3 × 4 + 3 × 4 × 5 + ..... +n (n + 1).( n + 2)$
⇒ $D = [n(2n - 1 +1)] : 2 = n.2n : 2 = 2n^2 : 2 = n^2$