\(x^3+6x^2+13x+12=0\\↔x^3+3x^2+3x^2+4x+9x+12=0\\↔(x^3+3x^2+4x)+(3x^2+9x+12)=0\\↔x(x^2+3x+4)+3(x^2+3x+4)=0\\↔(x+3)(x^2+3x+4)=0\\TH1:x+3=0\\↔x=-3\\TH2:x^2+3x+4=0\\↔x^2+2.\dfrac{3}{2}.x+\dfrac{9}{4}+\dfrac{7}{4}=0\\↔(x+\dfrac{3}{2})^2+\dfrac{7}{4}=0(vo\,\,ly)\\Suy\,\,ra:x=-3\\Vay\,\,pt\,\,co\,\,tap\,\,nghiem\,\,S=\{-3\}\)