Đáp án:
`e)5x²-5/{3}x=0`
`⇒5x(x-1/3)=0`
⇒\(\left[ \begin{array}{l}5x=0\\x-1/3=0\end{array} \right.\)
⇒\(\left[ \begin{array}{l}x=0\\x=1/3\end{array} \right.\)
`f)|3x-4|+|3y+5|=0`
⇒$\left \{ {{|3x-4|≥0} \atop {|3y+5|≥0}} \right.$
⇒\(\left[ \begin{array}{l}3x-4=0\\3y+5=0\end{array} \right.\)
⇒\(\left[ \begin{array}{l}x=4/3\\y=-5/3\end{array} \right.\)