Đáp án:
a. x=5
Giải thích các bước giải:
\(\begin{array}{l}
a.DK:x \ne \left\{ { - 3;2} \right\}\\
Pt \to \frac{{2x\left( {x - 2} \right) - \left( {x - 1} \right)\left( {x + 3} \right) - x + 7}}{{\left( {x + 3} \right)\left( {x - 2} \right)}} = 0\\
\to 2{x^2} - 4x - {x^2} - 2x + 3 - x + 7 = 0\\
\to {x^2} - 7x + 10 = 0\\
\to {x^2} - 5x - 2x + 10 = 0\\
\to x\left( {x - 5} \right) - 2\left( {x - 5} \right) = 0\\
\to \left[ \begin{array}{l}
x - 5 = 0\\
x - 2 = 0
\end{array} \right.\\
\to \left[ \begin{array}{l}
x = 5\\
x = 2\left( l \right)
\end{array} \right.
\end{array}\)
\(\begin{array}{l}
b.\frac{{15x - 15 - 10\left( {2x + 3} \right) - 6x - 4.30}}{{30}} \le 0\\
\to 15x - 15 - 20x - 30 - 6x - 120 \le 0\\
\to - 11x \le 165\\
\to x \ge - 15
\end{array}\)
