Đáp án:
49D
50A
Giải thích các bước giải:
\(\begin{array}{l}
49.\\
\frac{{{p_1}{V_1}}}{{{T_1}}} = \frac{{{p_2}{V_2}}}{{{T_2}}}\\
\frac{{{{10}^5}.100}}{{27 + 273}} = \frac{{{p_2}20}}{{327 + 273}}\\
{p_2} = {10^6}pa\\
D\\
50.\\
\frac{{{p_1}{V_1}}}{{{T_1}}} = \frac{{{p_2}{V_2}}}{{{T_2}}}\\
\frac{{750.40}}{{300}} = \frac{{1500.{V_2}}}{{150}}\\
{V_2} = 10c{m^3}
\end{array}\)
A
