Đáp án:
Giải thích các bước giải:
$1/$
$a,C+O_2\buildrel{{t^o}}\over\longrightarrow$ $CO_2$
$S+O_2\buildrel{{t^o}}\over\longrightarrow$ $SO_2$
$4P+5O_2\buildrel{{t^o}}\over\longrightarrow$ $2P_2O_5$
$2Zn+O_2\buildrel{{t^o}}\over\longrightarrow$ $2ZnO$
$4Al+3O_2\buildrel{{t^o}}\over\longrightarrow$ $2Al_2O_3$
$3Fe+2O_2\buildrel{{t^o}}\over\longrightarrow$ $Fe_3O_4$
$2Cu+O_2\buildrel{{t^o}}\over\longrightarrow$ $2CuO$
$CH_4+2O_2\buildrel{{t^o}}\over\longrightarrow$ $CO_2+H_2O$
$C_2H_6O+3O_2\buildrel{{t^o}}\over\longrightarrow$ $2CO_2+3H_2O$
$b,2KClO_3\buildrel{{đp}}\over\longrightarrow$ $2KCl+3O_2$
$2KMnO_4\buildrel{{đp}}\over\longrightarrow$ $K_2MnO_4+MnO_2+O_2$
$2/$
$a,PTPƯ:4Al+3O_2\buildrel{{t^o}}\over\longrightarrow$ $2Al_2O_3$
$b,n_{Al}=\frac{10,8}{27}=0,4mol.$
$Theo$ $pt:$ $n_{O_2}=\frac{3}{4}n_{Al}=0,3mol.$
$⇒V_{O_2}=0,3.22,4=6,72l.$
$c,Theo$ $pt:$ $n_{Al_2O_3}=\frac{1}{2}n_{Al}=0,2mol.$
$⇒m_{Al_2O_3}=0,2.102=20,4g.$
$3/$
$PTPƯ:2KClO_3\buildrel{{đp}}\over\longrightarrow$ $2KCl+3O_2$
$n_{KClO_3}=\frac{49}{122,5}=0,4mol.$
$Theo$ $pt:$ $n_{O_2}=\frac{3}{2}n_{KMnO_4}=0,6mol.$
$⇒V_{O_2}=0,6.22,4=13,44l.$
$4/$
$CO_2→H_2CO_3$
$P_2O_5→H_3PO_4$
$SO_3→H_2SO_4$
$N_2O_5→HNO_3$
$SiO_2→H_2SiO_3$
$SO_2→H_2SO_3$
$Na_2O→NaOH$
$K_2O→KOH$
$BaO→Ba(OH)_2$
$Al_2O_3→Al(OH)_3$
$Fe_2O_3→Fe(OH)_3$
$FeO→Fe(OH)_2$
chúc bạn học tốt!
