$\text{Bài 1}$
$\text{Hình thứ nhất}$
$AH=AC.sinC$
$→x=11.sin38^o≈6,77$
$AH=AB.sinB$
$→y=\dfrac{6,77}{sin30}=13,54$
$\text{Hình thứ hai:}$
$AH=AB.sinB$
$→x=8.sin30^o=4cm$
$AH=AC.cos\widehat{HAC}$
$→y=\dfrac{4}{cos50^o}≈6,22$
$\text{Bài 2}$
$AC=CB.sinB$
$→x=7.sin40^o≈4,5$
$AD=AC.cot\widehat{ADC}$
$→y=4,5.cot60^o=\dfrac{3\sqrt{3}}{2}$
$......................$
$CDPQ$ là hình vuông
$CB=\dfrac{CQ}{cos\widehat{QCB}}$
$→x=\dfrac{4}{cos50^o}≈6,22$
$AP=DP.cotA=4.cot70^o≈1,46$
$QB=CB.sin\widehat{CQB}=6,22.sin50^o≈4,76$
$y=AP+PQ+QB=1,46+4+4,76=10,22$
