Em tham khảo nha:
\(\begin{array}{l}
1)\\
a)\\
Mg + 2HCl \to MgC{l_2} + {H_2}\\
Fe + 2HCl \to FeC{l_2} + {H_2}\\
Zn + 2HCl \to ZnC{l_2} + {H_2}\\
b)\\
Mg + FeC{l_2} \to MgC{l_2} + Fe\\
Zn + FeC{l_2} \to ZnC{l_2} + Fe\\
c)\\
Mg + 2AgN{O_3} \to Mg{(N{O_3})_2} + 2Ag\\
Fe + 2AgN{O_3} \to Fe{(N{O_3})_2} + 2Ag\\
Cu + 2AgN{O_3} \to Cu{(N{O_3})_2} + 2Ag\\
Zn + 2AgN{O_3} \to Zn{(N{O_3})_2} + 2Ag\\
2)\\
a)\\
Zn + 2HCl \to ZnC{l_2} + {H_2}\\
{n_{{H_2}}} = \dfrac{{4,48}}{{22,4}} = 0,2\,mol\\
{n_{Zn}} = {n_{{H_2}}} = 0,2\,mol\\
\% {m_{Zn}} = \dfrac{{0,2 \times 65}}{{21}} \times 100\% = 61,9\% \\
\% {m_{Cu}} = 100 - 61,9 = 38,1\% \\
b)\\
{n_{HCl}} = 2{n_{{H_2}}} = 2 \times 0,2 = 0,4\,mol\\
{V_{{\rm{dd}}HCl}} = \dfrac{{0,4}}{{1,5}} = 0,267l
\end{array}\)
