Đáp án:
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Giải thích các bước giải:
a,
\(\begin{array}{l}
{m_{Cu}} = \dfrac{{40 \times 160}}{{100}} = 64g\\
{m_S} = \dfrac{{20 \times 160}}{{100}} = 32g\\
{m_O} = \dfrac{{40 \times 160}}{{100}} = 64g\\
\to {n_{Cu}}:{n_S}:{n_O} = 1:1:4\\
\to CuS{O_4}
\end{array}\)
b,
\(\begin{array}{l}
{m_N} = \dfrac{{82,35 \times 17}}{{100}} = 14g\\
{m_H} = \dfrac{{17,65 \times 17}}{{100}} = 3g\\
\to {n_N}:{n_H} = 1:3\\
\to N{H_3}
\end{array}\)
c,
\(\begin{array}{l}
{m_{Na}} = \dfrac{{32,39 \times 142}}{{100}} = 46g\\
{m_S} = \dfrac{{22,53 \times 142}}{{100}} = 32g\\
{m_O} = \dfrac{{45,08 \times 142}}{{100}} = 64g\\
\to {n_{Na}}:{n_S}:{n_O} = 2:1:4\\
\to N{a_2}S{O_4}
\end{array}\)
d,
\(\begin{array}{l}
{m_{Fe}} = \dfrac{{36,8 \times 152}}{{100}} = 56g\\
{m_S} = \dfrac{{21 \times 152}}{{100}} = 32g\\
{m_O} = \dfrac{{42,2 \times 152}}{{100}} = 64g\\
\to {n_{Fe}}:{n_S}:{n_O} = 1:1:4\\
FeS{O_4}
\end{array}\)
e,
\(\begin{array}{l}
{m_C} = \dfrac{{80 \times 30}}{{100}} = 24g\\
{m_H} = \dfrac{{20 \times 30}}{{100}} = 6g\\
\to {n_C}:{n_C} = 2:6\\
{C_2}{H_6}
\end{array}\)
f,
\(\begin{array}{l}
{m_C} = \dfrac{{23,8 \times 50,5}}{{100}} = 12g\\
{m_H} = \dfrac{{5,9 \times 50,5}}{{100}} = 3g\\
{m_{Cl}} = \dfrac{{70,3 \times 50,5}}{{100}} = 35,5g\\
\to {n_C}:{n_H}:{n_{Cl}} = 1:3:1\\
\to C{H_3}Cl
\end{array}\)
e,
\(\begin{array}{l}
{m_C} = \dfrac{{40 \times 180}}{{100}} = 72g\\
{m_H} = \dfrac{{6,7 \times 180}}{{100}} = 12g\\
{m_O} = \dfrac{{53,3 \times 180}}{{100}} = 96g\\
\to {n_C}:{n_H}:{n_O} = 6:12:6\\
\to {C_6}{H_{12}}{O_6}
\end{array}\)
