`b,n` $\vdots$ `150` và `n` $\vdots$ `270`
`=>n ∈ BCNN_((150;270))`
Ta có:
`150=2.3.5^2`
`270=2.5.3^3`
`=>BCNN_((150;270))=3^3 . 5^2 .2=1350`
Vậy `n=1350`
`d,n` $\vdots$ `175` và `n` $\vdots$ `300`
`=>n ∈ BCNN_((175;300))`
Ta có:
`175=7.5^2`
`300=5^2 . 2^2 . 3`
`=>BCNN_((175;300))=5^2 . 7. 3 . 2^2=2100`
Vậy `n=2100`