$\sqrt[]{Δ}$=$\sqrt[]{25+4\sqrt[]{6}}$
=$\sqrt[]{24+2*2\sqrt[]{6}*1+1}$
=$\sqrt[]{(2\sqrt[]{6}+1)²}$
=|$2\sqrt[]{6}$+1|
=2$\sqrt[]{6}$+1
⇒x1=$\frac{-5+2\sqrt[]{6}+1}{2\sqrt[]{3}}$
=$\frac{2\sqrt[]{6}-4}{2\sqrt[]{3}}$
=$\frac{\sqrt[]{6}-2}{\sqrt[]{3}}$
x2=$\frac{-5-2\sqrt[]{6}-1}{2\sqrt[]{3}}$
=$\frac{-2\sqrt[]{6}-6}{2\sqrt[]{3}}$
=$\frac{-\sqrt[]{6}-3}{\sqrt[]{3}}$
