Đáp án:
\(\begin{array}{l}
a)\\
{V_{{H_2}}} = 3,92l\\
b)\\
H = 80\%
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
a)\\
2C{H_3}COOH + 2Na \to 2C{H_3}COONa + {H_2}\\
{n_{C{H_3}COOH}} = \dfrac{{21}}{{60}} = 0,35\,mol\\
{n_{{H_2}}} = \dfrac{{0,35}}{2} = 0,175\,mol\\
{V_{{H_2}}} = 0,175 \times 22,4 = 3,92l\\
b)\\
C{H_3}COOH + {C_2}{H_5}OH \to C{H_3}COO{C_2}{H_5} + {H_2}O\\
{n_{C{H_3}COO{C_2}{H_5}}} = {n_{C{H_3}COOH}} = 0,35\,mol\\
H = \dfrac{{24,64}}{{0,35 \times 88}} \times 100\% = 80\%
\end{array}\)
