a.$\frac{x-3}{5}$ =6-$\frac{1-2x}{3}$ <=> $\frac{x-3}{5}$=$\frac{18-1+2x}{3}$ <=>$\frac{x-3}{5}$=$\frac{17+2x}{3}$ <=>$\frac{3.(x-3)}{3.5}$=$\frac{5.(17+2x)}{5.3}$<=>5.(17+2x)=3.(x-3)
⇔85+10x=3x-9⇔7x=-94⇔x=-94/7
b.
$\frac{2x}{3}$ +$\frac{2x-1}{6}$ =4-$\frac{x}{3}$ <=> $\frac{6x-1}{6}$ =$\frac{12-x}{3}$ <=> $\frac{6x-1}{6}$ =$\frac{2.(12-x)}{2.3}$ <=> 6x-1=24-2x<=>8x=25<=>x=$\frac{25}{8}$
c.$\frac{7x}{8}$ -5(x-9)=$\frac{20x+1,5}{6}$ <=>$\frac{7x}{8}$-$\frac{8.5.(x-9)}{8}$ =$\frac{20x+1,5}{6}$<=>$\frac{7x-40x+360}{8}$ =$\frac{20x+1,5}{6}$<=>$\frac{-33x+360}{8}$=$\frac{20x+1,5}{6}$<=> $\frac{3.(-33x+360)}{3.8}$ =$\frac{4.(20x+1,5)}{4.6}$<=>3.(-33x+360)=4.(20x+1,5)<=>-99x+1080=80x+6<=>179x=1074<=>x=6
d.$\frac{5.(x-1)+2}{3}$ -$\frac{9x-1}{4}$ =$\frac{2.(3x+1)}{5}$ -1<=>$\frac{4.[5.(x-1)+2]}{4.3}$ -$\frac{3.(9x-1)}{3.4}$ =$\frac{2.(3x-1)-5}{5}$ <=>$\frac{20x-20+8-27x+3}{12}$ =$\frac{6x-2-5}{5}$<=> $\frac{-7x-9}{12}$ =$\frac{6x-7}{5}$ <=> $\frac{5.(-7x-9)}{5.12}$=$\frac{12.(6x-7)}{12.5}$<=>5.(-7x-9)=12.(6x-7)<=>-35x-45=72x-84<=>107x=39<=>x=$\frac{39}{107}$
cho mk câu trả lời hay nhất nha:3
đánh máy lâu lắm :(
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