e) (x+1)^2 =4(x^2 - 2x +1)^2
<=> (x+1)^2 = 2^2 . (x-1)^2
<=> (x+1)^2 = [2. (x-1)]^2
<=>
TH1 : x+1 = 2(x-1) => x = 3
TH2 : x+1 = - 2 (x-1) => 3x = 1 => x= 1/3
Vậy x = 1/3 hoặc 3
d) 9(x-3)^2 = 4(x+2)^2
<=> [3 (x-3)] ^2 = [2 . (x+2) ] ^2
<=> TH1
3(x-3)= 2(x+2) => x = 13
TH2 :
3(x-3) = -2(x+2) =>> 5x = 5 =. x =1
Vậy x = 1 hoặc 13