`b) 1 - 4/5 : ( 1 1/5 - 3/2x) = 2/3`
`4/5 : ( 6/5 - 3/2x) = 1 - 2/3`
`4/5 : ( 6/5 - 3/2x) = 1/3`
`( 6/5 - 3/2x) = 4/5 : 1/3`
`( 6/5 - 3/2x) = 4/5 . 3/1`
`6/5 - 3/2x = 12/5`
`3/2 x = 6/5 - 12/5`
`3/2 x = -6/5`
`x = -6/5 : 3/2`
`x= -4/5`
Vậy `x = -4/5`
`#caty09`