a) ($2x-3^{}$ )-($x-5^{}$ )= ($x+2^{}$ )-($x-1^{}$ )
<=> ($2x-3^{}$ )-($x-5^{}$ )- ($x+2^{}$ )+($x-1^{}$ )=0
<=>$2x-3^{}$ -$x+5^{}$ - $x-2^{}$ +$x-1^{}$ =0
<=>$x^{}$ $-1^{}$ =0
=>$x^{}$ =$1^{}$
b)$2(x-1)^{}$ - $5(x+2)^{}$=$-10^{}$
<=> $2(x-1)^{}$ - $5(x+2)^{}$+$10=0^{}$
<=> $2x-2-5x-10+10=0^{}$
<=>$-3x-2=0^{}$
=>$x=\frac{-2}{3}$
Vote 5s+Ctlhn cho mị nhé!!!