a)$(3x-2)-(2x+1)=5(x-1)$
$ 3x-2-2x-1=5x-5$
$ (3x-2x)-(2+1)=5x-5$
$ x-3 = 5x-5$
$x-5x=3-5$
$-4x = 2$
⇒$x=\frac{-1}{2}$
b)$3x-|x|=2x$
$|x|=3x-2x$
$|x|=x$
⇒$x=x$ hoặc $x=-x$
⇒ $x$ tùy ý
c)$(3x-1)²=25$
⇒\(\left[ \begin{array}{l}3x-1=5\\3x-1=-5\end{array} \right.\)
⇒\(\left[ \begin{array}{l}3x=6\\3x=-4\end{array} \right.\)
⇒\(\left[ \begin{array}{l}x=2\\x=\frac{-4}{3}\end{array} \right.\)
d)$25x²-4x=0$
$x(25x-4)=0$
⇒\(\left[ \begin{array}{l}x=0\\25x-4=0\end{array} \right.\)
⇒\(\left[ \begin{array}{l}x=0\\25x=4\end{array} \right.\)
⇒\(\left[ \begin{array}{l}x=0\\x=\frac{4}{25}\end{array} \right.\)
e)$\frac{1}{2}(x-3)-(x+1)=\frac{2}{3}(1-x)$
$\frac{1}{2}x-\frac{3}{2}-x-1=\frac{2}{3}-\frac{2}{3}x$
$(\frac{1}{2}x-x+\frac{2}{3}x)=(\frac{2}{3}+\frac{3}{2}-1)$
$\frac{1}{6}x = \frac{7}{6}$
$x = \frac{7}{6}:\frac{1}{6}$
$x=7$
