a)
Ta có:
\({m_{dd{\text{ HCl}}}} = 1000.1,1 = 1100{\text{ gam}}\)
\({m_{HCl}} = 1100.25\% = 275{\text{ gam}}\)
\( \to {n_{HCl}} = \frac{{275}}{{36,5}} = 7,5342{\text{ mol}}\)
\( \to {C_{M{\text{ HCl}}}} = \frac{{7,5342}}{1} = 7,5342M\)
\( \to [{H^ + }] = [C{l^ - }] = 7,5342M\)
b)
Ta có:
\({m_{dd{\text{HN}}{{\text{O}}_3}}} = 1000.1,054 = 1054{\text{ gam}}\)
\( \to {m_{HN{O_3}}} = 1054.10\% = 105,4{\text{ gam}}\)
\( \to {n_{HN{O_3}}} = \frac{{105,4}}{{63}} = 1,673{\text{ mol}}\)
\( \to {C_{M{\text{ HN}}{{\text{O}}_3}}} = \frac{{1,673}}{1} = 1,673M\)
\( \to [{H^ + }] = [N{O_3}^ - ] = 1,673M\)
c)
Ta có:
\({m_{dd\;{{\text{H}}_2}S{O_4}}} = 1000.1,025 = 1025{\text{ gam}}\)
\( \to {m_{{H_2}S{O_4}}} = 1025.3,92\% = 40,18{\text{ gam}}\)
\( \to {n_{{H_2}S{O_4}}} = \frac{{40,18}}{{98}} = 0,41{\text{ mol}}\)
\( \to {C_{M{\text{ }}{{\text{H}}_2}S{O_4}}} = \frac{{0,41}}{1} = 0,41M\)
\( \to [{H^ + }] = 0,82M;[S{O_4}^{2 - }] = 0,41M\)
