a.
PTPU: Zn+2HCl->ZNCl2+H2O
nZnO=16,2/81=0,2(mol)
nHCl=2nZn=0,4(mol)
CMHCl=0,4/0,2=2(M)
b.
Theo PT ta có: nZnCl2=nZnO=0,2(mol)
=>mZnCl2=0,2x136=27,2(gam)
c.
PTPU: HCl+NaOH->NaCl+H2O
nNaOH=nHCl=0,4(mol)
=>mNaOH=0,4x40=16(gam)
=>mddNaOH=16x100/15=106,67(gam)
=>vNaOH=106,67/1,12=95,24(ml)