Đáp án:
\({C_{M{\text{ }}{{\text{H}}_2}S{O_3}}} = 1,2M\)
\(C{\% _{{H_2}S{O_3}}} = 7,28\% \)
Giải thích các bước giải:
Phản ứng xảy ra:
\(S{O_2} + {H_2}O\xrightarrow{{}}{H_2}S{O_3}\)
Ta có:
\({n_{S{O_2}}} = \frac{{6,72}}{{22,4}} = 0,3{\text{ mol = }}{{\text{n}}_{{H_2}S{O_3}}}\)
\({V_{dd}} = 250{\text{ ml = 0}}{\text{,25 lít}}\)
\( \to {C_{M{\text{ }}{{\text{H}}_2}S{O_3}}} = \frac{{0,3}}{{0,25}} = 1,2M\)
\({m_{{H_2}S{O_3}}} = 0,25.(1.2 + 32 + 16.3) = 20,5{\text{ gam}}\)
\({m_{dd{\text{ A}}}} = 250.1,125 = 281,25{\text{ gam}}\)
\( \to C{\% _{{H_2}S{O_3}}} = \frac{{20,5}}{{281,25}} = 7,28\% \)
