`d)` |`x + 1/3`| `- 4 = -1`
`⇒` |`x + 1/3`| `= 3`
`⇒ x + 1/3 = 3` hoặc `x + 1/3 = -3`
`⇒ x = 8/3` hoặc `x = -10/3`
`(1/5)^300` và `(1/3)^500`
Ta có: `(1/5)300 = ((1/5)^3)^100 = (1/125)^100`
`(1/3)^500 = ((1/3)^5)^100 = (1/243)^100`
Vì `(1/125)^100 > (1/243)^100`
`⇒ (1/5)^300 > (1/3)^500`