Đáp án:
23.
a. x=14
b. \(-27<x<1\)
Giải thích các bước giải:
23.
a. \(\frac{8}{17}+\frac{5}{17}< \frac{x}{17}<\frac{6}{17}+\frac{9}{17}\)
\(\leftrightarrow \frac{13}{17}<\frac{x}{17}<\frac{15}{17}\)
\(\leftrightarrow 13<x<15\)
Vậy \(x =14\)
b. \(-\frac{6}{7}+\frac{3}{35}<\frac{x}{35}<\frac{-2}{5}+\frac{3}{7}\)
\(\leftrightarrow \frac{-6.5}{35}+\frac{3}{35}<\frac{x}{35}<\frac{-2.7}{35}+\frac{3.5}{35}\)
\(\leftrightarrow \frac{-27}{35}<\frac{x}{35}<\frac{1}{35}\)
\(\leftrightarrow -27<x<1\)
Vậy \(-27<x<1\)
\(x \epsilon \) {-26,-25,-24....,-1,0}