VD1:
Phản ứng xảy ra:
\(Cu + 2{H_2}S{O_4}\xrightarrow{{{t^o}}}CuS{O_4} + S{O_2} + 2{H_2}O\)
Ta có:
\({n_{Cu}} = \frac{{6,4}}{{64}} = 0,1{\text{ mol = }}{{\text{n}}_{S{O_2}}}\)
\( \to V = {V_{S{O_2}}} = 0,1.22,4 = 2,24{\text{ lít}}\)
VD2:
Phản ứng xảy ra:
\(2Fe + 6{H_2}S{O_4}\xrightarrow{{{t^o}}}F{e_2}{(S{O_4})_3} + 3S{O_2} + 6{H_2}O\)
\({n_{S{O_2}}} = \frac{{6,72}}{{22,4}} = 0,3{\text{ mol}}\)
\( \to {n_{Fe}} = \frac{2}{3}{n_{S{O_2}}} = 0,2{\text{ mol}}\)
\( \to m = {m_{Fe}} = 0,2.56 = 11,2{\text{ gam}}\)
