Đáp án:
a. nC2H2=4.48/22.4=0.2mol
2C2H2+5O2->2CO2+4H2O
nO2= 5/2nC2H2=5/2*0.2=0.5mol
vO2=0.5*22.4=11.2lit
vKK=5vO2=5*11.2=56lit
b. nCO2=nC2H2=0.2mol
nH2O=n2nC2H2=2*0.2=0.4mol
mCO2=0.2*44=8.8gam
mH2O=0.4*18=7.2gam
c. 2KClO3 → 2KCl + 3O2
nKClO3=2/3nO2=2/3*0.5=0.333mol
mKClO3=0.333*122.5=40.83gam