Đáp án:
1M
0,2l
Giải thích các bước giải:
\(\begin{array}{l}
B1:\\
2C{H_3}COOH + CaC{O_3} \to {(C{H_3}COO)_2}Ca + C{O_2} + {H_2}O\\
nC{O_2} = \dfrac{{2,24}}{{22,4}} = 0,1\,mol\\
nC{H_3}COOH = 0,1 \times 2 = 0,2\,mol\\
CMC{H_3}COOH = \dfrac{{0,2}}{{0,2}} = 1M\\
B2:\\
C{H_3}COOH + NaOH \to C{H_3}COONa + {H_2}O\\
nC{H_3}COOH = \dfrac{{200 \times 6\% }}{{60}} = 0,2\,mol\\
nNaOH = nC{H_3}COOH = 0,2\,mol\\
VNaOH = \dfrac{{0,2}}{1} = 0,2l
\end{array}\)
