Đáp án + Giải thích các bước giải:
`a, |x-1/3| : 2 = (-2)^2 + 4/6`
`=> |x-1/3| : 2 = 14/3`
`=> |x-1/3| = 14/3 xx 2`
`=> |x-1/3| = 28/3`
\(⇒\left[ \begin{array}{l}x-\dfrac{1}3=\dfrac{28}3\\x-\dfrac{1}3=-\dfrac{28}3\end{array} \right.\)
\(⇒\left[ \begin{array}{l}x=\dfrac{28}3+\dfrac{1}3\\x=-\dfrac{28}3+\dfrac{1}3\end{array} \right.\)
\(⇒\left[ \begin{array}{l}x=\dfrac{29}3\\x=-\dfrac{27}3\end{array} \right.\)
Vậy `x={29/3;-27/3}`
`b, (x+1/10)^2 + 5/16 = 14/3 . 3/16`
`=> (x+1/10)^2 + 5/16 = 7/8`
`=> (x+1/10)^2 = 7/8 - 5/16`
`=> (x+1/10)^2 = 9/16`
\(⇒\left[ \begin{array}{l}x+\dfrac{1}{10}=\dfrac{3}4\\x+\dfrac{1}{10}=-\dfrac{3}4\end{array} \right.\)
\(⇒\left[ \begin{array}{l}x=\dfrac{3}4-\dfrac{1}{10}\\x=-\dfrac{3}4-\dfrac{1}{10}\end{array} \right.\)
\(⇒\left[ \begin{array}{l}x=\dfrac{13}{20}\\x=-\dfrac{17}{20}\end{array} \right.\)
Vậy `x={13/20;-17/20}`
