Đáp án: x = \(\frac{8}{3}\)
\(\frac{3x +2}{3x-2}\) - \(\frac{6}{3x-2}\) = \(\frac{9x²}{9x²-4}\) (1)
ĐK: x \(\neq \) \(\frac{2}{3}\); \(\frac{-2}{3}\)
(1) => \(\frac{(3x +2)² - 6(3x-2)}{9x²-4}\) = \(\frac{9x²}{9x²-4}\)
=> 9x² + 12x +4 - 18x +12 = 9x²
=> -6x + 16 = 0
=> x = \(\frac{-16}{-6}\)
=> x = \(\frac{8}{3}\) (TMĐK)
Vậy x = \(\frac{8}{3}\)