a) `4x^2-9=0`
⇔`(2x-3)(2x+3)=0`
⇔\(\left[ \begin{array}{l}2x-3=0\\2x+3=0\end{array} \right.\)
⇔\(\left[ \begin{array}{l}x=\frac{3}{2}\\x=-\frac{3}{2}\end{array} \right.\)
Vậy `S={3/2,-3/2}`
b) `x^3+3x=3x^2+1`
⇔`x^3+3x-3x^2-1=0`
⇔`(x-1)^3=0`
⇔`x-1=0`
⇔`x=1`
Vậy `S={1}`