Em tham khảo nha:
\(\begin{array}{l}
10)\\
{M_A} = {d_{A/{O_2}}} \times {M_{{O_2}}} = 1,375 \times 32 = 44g/mol\\
11)\\
{M_A} = {d_{A/kk}} \times 29 = 2,207 \times 29 = 64g/mol\\
12)\\
{m_{{\rm{dd}}NaCl}} = {m_{NaCl}} + {m_{{H_2}O}} = 20 + 80 = 100g\\
13)\\
{m_{{\rm{dd}}{{\rm{K}}_2}S{O_4}}} = {m_{{K_2}S{O_4}}} + {m_{{H_2}O}} = 10 + 40 = 50g\\
{C_\% }{K_2}S{O_4} = \dfrac{{{m_{{K_2}S{O_4}}}}}{{{m_{{\rm{dd}}{K_2}S{O_4}}}}} \times 100\% = \dfrac{{10}}{{50}} \times 100\% = 20\% \\
14)\\
{m_{KOH}} = \dfrac{{250 \times 2}}{{100}} = 5g\\
15)\\
{m_{{\rm{dd}}Ba{{(OH)}_2}}} = \dfrac{{15 \times 100}}{{10}} = 150g
\end{array}\)
