Phản ứng xảy ra
\[2M+ 3Cl_2\to 2MCl_3\]
\[n_M=n_{MCl_3}\]
\[\to \dfrac{10,8}{M}=\dfrac{53,4}{M+35,5.3}\]
$\to M=27$
$\to A$ là $Al$
$\color{SeaGreen}{\mathcal{HAVE}}$ $\color{RoyalBlue}{\mathcal{A}}$ $\color{Thistle}{\mathcal{GOOD}}$ $\color{Salmon}{\mathcal{DAY}}$ $\color{Gray}{\mathcal{!!}}$