Giải thích các bước giải:
\(\begin{array}{l}
b.\left[ \begin{array}{l}
y = 0\\
y = \frac{1}{2}\\
y = - \frac{5}{2}
\end{array} \right.\\
c.{\left( {2y - 1} \right)^2} = 0\\
\to y = \frac{1}{2}\\
d.\left( {y - 10} \right)\left( {y + 8} \right) = 0\\
\to \left[ \begin{array}{l}
y = 10\\
y = - 8
\end{array} \right.\\
g.4{y^2} - 4y + 1 - {y^2} - 6y - 9 = 0\\
\to \left( {y - 4} \right)\left( {3y + 2} \right) = 0\\
\to \left[ \begin{array}{l}
y = 4\\
y = - \frac{2}{3}
\end{array} \right.\\
h.\left[ \begin{array}{l}
y = 0\\
y = \frac{{11}}{2}
\end{array} \right.\\
i.2{y^2} - y - 3 + {y^2} - 2y = 3{y^2} + 12y + 12\\
\to 15y = - 15\\
\to y = - 1\\
j.\left( {y - 4} \right)\left( {y + 2} \right) = 0\\
\to \left[ \begin{array}{l}
y = 4\\
y = - 2
\end{array} \right.\\
k.\left( {y + 2} \right)\left( {y + 3} \right) = 0\\
\to \left[ \begin{array}{l}
y = - 2\\
y = - 3
\end{array} \right.\\
l.\left[ \begin{array}{l}
y = \frac{{ - 7 + \sqrt {41} }}{2}\\
y = \frac{{ - 7 - \sqrt {41} }}{2}
\end{array} \right.\\
m.\left( {y - 4} \right)\left( {y + 3} \right) = 0\\
\to \left[ \begin{array}{l}
y = 4\\
y = - 3
\end{array} \right.
\end{array}\)
