Đáp án:
Phía dưới !!
Giải thích các bước giải:
a/ $|\frac{1}{2}x|=3-2x$
⇒ \(\left[ \begin{array}{l}\frac{1}{2}x=3-2x\\\frac{1}{2}x=-3+2x\end{array} \right.\)
⇒ \(\left[ \begin{array}{l}x=\frac{6}{5}\\x=2\end{array} \right.\)
b/ $|x-1|=3x+2$
⇒ \(\left[ \begin{array}{l}x-1=3x+2\\x-1=-3x-2\end{array} \right.\)
⇒ \(\left[ \begin{array}{l}x=-\frac{3}{2}\\x=-\frac{1}{4}\end{array} \right.\)
c/ $|5x|=x-12$
⇒ \(\left[ \begin{array}{l}5x=x-12\\5x=-x+12\end{array} \right.\)
⇒ \(\left[ \begin{array}{l}x=-3\\x=2\end{array} \right.\)
d/ $|17-x|=5x+1$
⇒ \(\left[ \begin{array}{l}17-x=5x+1\\17-x=-5x-1\end{array} \right.\)
⇒ \(\left[ \begin{array}{l}x=\frac{8}{3}\\x=-\frac{9}{2}\end{array} \right.\)
2/ a/ $|9+x|=2x$
⇒ \(\left[ \begin{array}{l}9+x=2x\\9+x=-2x\end{array} \right.\)
⇒ \(\left[ \begin{array}{l}x=9\\x=-3\end{array} \right.\)
b/ $|5x|-3x=2$
⇒ $|5x|=2+3x$
⇒ \(\left[ \begin{array}{l}5x=2+3x\\5x=-2-3x\end{array} \right.\)
⇒ \(\left[ \begin{array}{l}x=1\\x=-\frac{1}{4}\end{array} \right.\)
c/ $|x+6|-9=2x$
⇒ $|x+6|=2x+9$
⇒ \(\left[ \begin{array}{l}x+6=2x+9\\x+6=-2x-9\end{array} \right.\)
⇒ \(\left[ \begin{array}{l}x=-3\\x=-5\end{array} \right.\)
d/ $|2x-3|+x=21$
⇒ $|2x-3|=21-x$
⇒ \(\left[ \begin{array}{l}2x-3=21-x\\2x-3=-21+x\end{array} \right.\)
⇒ \(\left[ \begin{array}{l}x=8\\x=-18\end{array} \right.\)
Các bài còn lại tương tự nhé !!
chúc bạn học tốt !!!
