`#tnvt`
`\sqrt{x^2-4x+4}+1=3x`
`<=>\sqrt{x^2-4x+4}=3x-1(x>=1/3)`
`<=>\sqrt{(x-2)^2}=3x-1`
`<=>|x-2|=3x-1`
`<=>[(x-2=3x-1),(x-2=1-3x):}`
`<=>[(3x-x=-2+1),(x+3x=1+2):}`
`<=>[(2x=-1),(4x=3):}`
`<=>`$\left[\begin{matrix} x=-\dfrac{1}{2}(ktm) \\ x=\dfrac{3}{4}(tm)\end{matrix}\right.$
Vậy `x=3/4`
