Trình bày lời giải:
`a)`
`(x-1/2)^2=16`
`=>(x-1/2)^2=(+-4)^2`
`=>[(x-1/2=4),(x-1/2=-4):}`
`=>[(x=4+1/2),(x=-4+1/2):}`
`=>[(x=8/2+1/2),(x=-8/2+1/2):}`
`=>[(x=9/2),(x=-7/2):}`
Vậy `x\in{9/2;-7/2}`
`b)`
`(x+2)/3=(x-1)/4`
`=>(x+2).4=3.(x-1)`
`=>4x+8=3x-3`
`=>4x-3x=-3-8`
`=>x=-11`
Vậy `x=-11`
`c)`
`1/3-1/3.(x-1)=2`
`=>1/3.(x-1)=1/3-2`
`=>1/3.(x-1)=1/3-6/3`
`=>1/3.(x-1)=-5/3`
`=>x-1=-5/3:1/3`
`=>x-1=-5/3 . 3/1`
`=>x-1=-5`
`=>x=-5+1`
`=>x=-4`
Vậy `x=-4`
`d)`
`|2x-1 1/2|=3`
`=>|2x-3/2|=3`
`=>[(2x-3/2=3),(2x-3/2=-3):}`
`=>[(2x=3+3/2),(2x=-3+3/2):}`
`=>[(2x=6/2+3/2),(2x=-6/2+3/2):}`
`=>[(2x=9/2),(2x=-3/2):}`
`=>[(x=9/2:2),(x=-3/2:2):}`
`=>[(x=9/2 . 1/2),(x=-3/2 . 1/2):}`
`=>[(x=9/4),(x=-3/4):}`
Vậy `x\in{9/4;-3/4}`
