$\text{Ta có:}$
$2^{a - 6} . (\dfrac{7}{2})^{b} = 28^{a}$
$⇒ 2^{a - 6} . \dfrac{7^{b}}{2^{b}} = (7 . 2^{2})^{a}$
$⇒ 2^{a - 6 - a} . 7^{b} = 7^{a} . 2^{2a}$
$⇒ a - 6 - b = 2a ; b = a$
$⇒ a - 6 - a = 2a ; b = a$
$⇒ -2a = 6 ; b = a$
$⇒ a = -3 ; b = a = -3$
$⇒ a + b = -3 + (-3) = -6$
$\text{Vậy}$ $a + b = -6$