`ĐKXĐ:`
\(\left\{ \begin{array}{l}2x - 3a - 4 ≥ 0\\x + a - 2 \ne 0\end{array} \right.\)
`<=>` \(\left\{ \begin{array}{l}x ≥ \dfrac{4 + 3a}{2}\\x \ne 2 - a\end{array} \right.\)
Để `x = (2; +∞)`
`<=> x > 2`
`=>` \(\left\{ \begin{array}{l}\dfrac{4 + 3a}{2} = 2 - a\\\dfrac{4 + 3a}{2} = 2\end{array} \right.\)
`<=>` \(\left\{ \begin{array}{l}4 + 3a = 4 - 2a\\4 + 3a = 4\end{array} \right.\)
`<=> a = 0`