Hai tập con của R là A và B. Hãy xác định \(A \cup {C_R}B;{C_R}A \cap B;{C_R}\left( {A \cup B} \right)\) và biểu diễn chúng trên trục số
a) \( A = \left( { - 1;0} \right];B = \left[ {0;2} \right) \)
b) \(A = \left[ {0;3} \right);B = \left( { - 1; + \infty } \right) \)
A.a) \( A \cup {C_R}B = \left( { - \infty ;0} \right] \cup \left[ {2; + \infty } \right);{C_R}A \cap B = \left( {0;2} \right);{C_R}\left( {A \cup B} \right) = \left( { - \infty ; - 1} \right) \cup \left[ {2; + \infty } \right)\)
b) \(A \cup {C_R}B = \left( { - \infty ; - 1} \right] \cup \left[ {0;3} \right);{C_R}A \cap B = \left( { - 1;0} \right) \cup \left[ {3; + \infty } \right);{C_R}\left( {A \cup B} \right) = \left( { - \infty ; - 1} \right] \)
B.a) \(A \cup {C_R}B = \left( { - \infty ;0} \right] \cup \left[ {2; + \infty } \right);{C_R}A \cap B = \left( {0;2} \right);{C_R}\left( {A \cup B} \right) = \left( { - \infty ; - 1} \right] \cup \left[ {2; + \infty } \right) \)
b) \( A \cup {C_R}B = \left( { - \infty ; - 1} \right] \cup \left[ {0;3} \right);{C_R}A \cap B = \left( { - 1;0} \right) \cup \left[ {3; + \infty } \right);{C_R}\left( {A \cup B} \right) = \left( { - \infty ; - 1} \right) \)
C.a) \( A \cup {C_R}B = \left( { - \infty ;0} \right] \cup \left[ {2; + \infty } \right);{C_R}A \cap B = \left[ {0;2} \right];{C_R}\left( {A \cup B} \right) = \left( { - \infty ; - 1} \right] \cup \left[ {2; + \infty } \right)\)
b) \( A \cup {C_R}B = \left( { - \infty ; - 1} \right] \cup \left[ {0;3} \right);{C_R}A \cap B = \left( { - 1;0} \right) \cup \left[ {3; + \infty } \right);{C_R}\left( {A \cup B} \right) = \left( { - \infty ; - 1} \right) \)
D.a) \( A \cup {C_R}B = \left( { - \infty ;0} \right] \cup \left[ {2; + \infty } \right);{C_R}A \cap B = \left( {0;2} \right);{C_R}\left( {A \cup B} \right) = \left( { - \infty ; - 1} \right] \cup \left[ {2; + \infty } \right) \)
b) \( A \cup {C_R}B = \left( { - \infty ; - 1} \right] \cup \left[ {0;3} \right);{C_R}A \cap B = \left( { - 1;0} \right) \cup \left[ {3; + \infty } \right);{C_R}\left( {A \cup B} \right) = \left( { - \infty ; - 1} \right] \)
a) \( A = \left( { - 1;0} \right];B = \left[ {0;2} \right) \)
b) \(A = \left[ {0;3} \right);B = \left( { - 1; + \infty } \right) \)
A.a) \( A \cup {C_R}B = \left( { - \infty ;0} \right] \cup \left[ {2; + \infty } \right);{C_R}A \cap B = \left( {0;2} \right);{C_R}\left( {A \cup B} \right) = \left( { - \infty ; - 1} \right) \cup \left[ {2; + \infty } \right)\)
b) \(A \cup {C_R}B = \left( { - \infty ; - 1} \right] \cup \left[ {0;3} \right);{C_R}A \cap B = \left( { - 1;0} \right) \cup \left[ {3; + \infty } \right);{C_R}\left( {A \cup B} \right) = \left( { - \infty ; - 1} \right] \)
B.a) \(A \cup {C_R}B = \left( { - \infty ;0} \right] \cup \left[ {2; + \infty } \right);{C_R}A \cap B = \left( {0;2} \right);{C_R}\left( {A \cup B} \right) = \left( { - \infty ; - 1} \right] \cup \left[ {2; + \infty } \right) \)
b) \( A \cup {C_R}B = \left( { - \infty ; - 1} \right] \cup \left[ {0;3} \right);{C_R}A \cap B = \left( { - 1;0} \right) \cup \left[ {3; + \infty } \right);{C_R}\left( {A \cup B} \right) = \left( { - \infty ; - 1} \right) \)
C.a) \( A \cup {C_R}B = \left( { - \infty ;0} \right] \cup \left[ {2; + \infty } \right);{C_R}A \cap B = \left[ {0;2} \right];{C_R}\left( {A \cup B} \right) = \left( { - \infty ; - 1} \right] \cup \left[ {2; + \infty } \right)\)
b) \( A \cup {C_R}B = \left( { - \infty ; - 1} \right] \cup \left[ {0;3} \right);{C_R}A \cap B = \left( { - 1;0} \right) \cup \left[ {3; + \infty } \right);{C_R}\left( {A \cup B} \right) = \left( { - \infty ; - 1} \right) \)
D.a) \( A \cup {C_R}B = \left( { - \infty ;0} \right] \cup \left[ {2; + \infty } \right);{C_R}A \cap B = \left( {0;2} \right);{C_R}\left( {A \cup B} \right) = \left( { - \infty ; - 1} \right] \cup \left[ {2; + \infty } \right) \)
b) \( A \cup {C_R}B = \left( { - \infty ; - 1} \right] \cup \left[ {0;3} \right);{C_R}A \cap B = \left( { - 1;0} \right) \cup \left[ {3; + \infty } \right);{C_R}\left( {A \cup B} \right) = \left( { - \infty ; - 1} \right] \)
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Hóa Học lớp 12
