n SO2 = 38,4/64=0,6(mol)
n NaOH=0,75.1=0,75(mol)
Đặt n Na2SO3=a(mol); n NaHSO3 = b(mol)
PTHH: 2NaOH + SO2 -> Na2SO3+H2O
(mol)____2a______a_________a___________
PTHH: NaOH+SO2-> NaHSO3
(mol)____b_______b_______b_______
Theo đề bài ta có:
2a+b=0,75
a+b=0,6
⇒ a=0,15;b=0,45
m Na2SO3 = 0,15.126=18,9(g)
m NaHSO3 = 0,45.104=46,8(g)